Hello (using version 2002

I am attempting to do some very basic cost loading in MS Project. I have a projects as tasks and I just want to generate a very simple cumulative cost curve using the Resource Graph. I want the cost to just spread across the timeline of the project (task). So far I am using the fixed cost field to load costs onto each project(task) and I have tried to get the Resource Graph to display a cumulative cost curve without using any resources. Is this possible? I don't want to use the "Analyze Timescaled Data in Excel" because I want to be able to print out the resource graph and the Gantt on the same page. If I need to use resources to get the resource graph to work can someone please give me steps involved? Thanks in advance.

Re: Cost Loading MS Project by Gérard

Gérard
Mon Jan 26 12:49:12 CST 2004

Hello Jeff,



I'm afraid your will be disappointed... :-(

First of all, it's not possible to get a Resource Graph without using any
resources.



Even if you would have resources assigned on tasks, it's impossible to print
out the Resource graph and the Gantt on the same page. You can print only
one view at a time.



Gérard Ducouret

"Jeff" <anonymous@discussions.microsoft.com> a écrit dans le message de
news: 3764B25F-D36C-4D02-B724-F77F1940B23B@microsoft.com...
> Hello (using version 2002)
>
> I am attempting to do some very basic cost loading in MS Project. I have
a projects as tasks and I just want to generate a very simple cumulative
cost curve using the Resource Graph. I want the cost to just spread across
the timeline of the project (task). So far I am using the fixed cost field
to load costs onto each project(task) and I have tried to get the Resource
Graph to display a cumulative cost curve without using any resources. Is
this possible? I don't want to use the "Analyze Timescaled Data in Excel"
because I want to be able to print out the resource graph and the Gantt on
the same page. If I need to use resources to get the resource graph to work
can someone please give me steps involved? Thanks in advance.
>