Re: Subnet question... by Ben
Ben
Wed Sep 01 06:15:55 CDT 2004
"Andy Foster" <andy.remove@andyfoster.this.com> wrote in message
news:2pkme2Fjoog1U1@uni-berlin.de...
>
> 172.41.48.1 /19 would be in the subnet 172.41.32.1 - 172.41.63.255 half of
> which isn't yours.
> /19 gives you 19 bits for the network, 13 bits for hosts, giving network
> increments of 32.0 (2^5 * 2^8)
> e.g. 172.41.0.0, 172.41.32.0, 172.41.64.0, 172.41.96.0, etc.
> You need at least /20 (20 bits for the network, 12 bits for the
host)giving
> network increments of 16.0 (2^4 * 2^8)
>
> If this is as clear as mud, try learntosubnet.com
>
>
I have to say www.learntosubnet.com is a great site! Thanks for posting this
link.
I have my 70-215 exam next week and I hope to be taking 70-218 & 70-214
soon, and subnetting is the one topic I'm finding difficult to master.
However I'm going through the videos on that site, and its a great help.
Very easy to understand!
Thanks
Ben